JEE Main & Advanced JEE Main Paper Phase-I (Held on 07-1-2020 Evening)

  • question_answer
    An ideal fluid flows (laminar flow) through a pipe of non-uniform diameter. The maximum and minimum diameters of the pipes are 6.4 cm and 4.8 cm, respectively. The ratio of the minimum and the maximum velocities of fluid in this pipe is:                                  [JEE MAIN Held on 07-01-2020 Evening]

    A) \[\frac{81}{256}\]      

    B) \[\frac{9}{16}\]

    C) \[\frac{3}{4}\]            

    D) \[\frac{\sqrt{3}}{2}\]

    Correct Answer: B

    Solution :

    [b] \[{{A}_{1}}{{v}_{1}}={{A}_{2}}{{v}_{2}}\] (Equation of continuity) \[\frac{{{v}_{\min }}}{{{v}_{\max }}}=\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}=\frac{{{(4.8)}^{2}}}{{{(6.4)}^{2}}}=\frac{9}{16}\]

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