A) \[\frac{1}{4}\,m/s\]
B) \[\frac{1}{2}\,m/s\]
C) \[1\,m/s\]
D) \[\frac{1}{8}\,m/s\]
Correct Answer: A
Solution :
[a] \[{{f}_{1}}={{f}_{0}}\frac{c}{c-v}\] \[{{f}_{2}}={{f}_{0}}\frac{c}{c+v}\] \[\Rightarrow \,\,2={{f}_{1}}-{{f}_{2}}={{f}_{0}}c\,\left[ \frac{1}{c-v}-\frac{1}{c+v} \right]\] \[=\,\,{{f}_{0}}c\,\frac{2v}{{{c}^{2}}\left[ 1-\frac{{{v}^{2}}}{{{c}^{2}}} \right]}\] \[\Rightarrow \,\,\,v=\frac{2c}{2{{f}_{0}}}=\frac{350}{1400}=\frac{1}{4}\,m/s\]You need to login to perform this action.
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