A) 1.06
B) 1.15
C) 1.46
D) 0.84
Correct Answer: A
Solution :
[a] \[I={{I}_{0}}=\left( 1-{{e}^{\frac{tR}{L}}} \right)\] \[{{I}_{\infty }}=I\,(t=\infty )\,={{I}_{0}}\] \[{{I}_{40}}=I(t=40\,s)={{I}_{0}}\,\left( 1-e\frac{-\,40\times 5}{10\times {{10}^{-\,3}}} \right)={{I}_{0}}\,(1-{{e}^{-\,20,000}})\]\[\Rightarrow \,\frac{{{I}_{\infty }}}{{{I}_{40}}}=\frac{1}{1\,-{{e}^{-\,20,\,000}}},\] which is slightly greater than 1You need to login to perform this action.
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