A) Direction of \[{{I}_{R}}\] remains unchanged and \[{{V}_{R}}\]is zero at t = 0.25
B) Direction of \[{{I}_{R}}\] remains unchanged and \[{{V}_{R}}\] is maximum at t = 0.5
C) At t = 0.5 direction of \[{{I}_{R}}\] reverses and \[{{V}_{R}}\]is zero
D) At t = 0.25 direction of \[{{I}_{R}}\] reverses and \[{{V}_{R}}\] is maximum
Correct Answer: C
Solution :
[c] \[I={{I}_{0}}t-{{I}_{0}}{{t}^{2}}\] \[\phi =\left( {{\mu }_{0}}nI \right)\times \left( \pi {{R}^{2}} \right)\] \[\therefore \varepsilon =\frac{-d\phi }{dt}\] \[\varepsilon ={{\mu }_{0}}n\pi {{R}^{2}}\left( {{I}_{0}}-2{{I}_{0}}t \right)\] \[\Rightarrow \varepsilon =0\] at \[t=\frac{1}{2}s\]You need to login to perform this action.
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