A) \[1.5\text{ }m{{s}^{1}}\]
B) \[1.9\text{ }m{{s}^{1}}\]
C) \[1.7\text{ }m{{s}^{1}}\]
D) \[2.0\text{ }m{{s}^{1}}\]
Correct Answer: B
Solution :
[b] \[{{F}_{total}}=Mg+\text{ }friction\] \[=2000\times 10+4000\] \[=20,000+4000=24000\text{ }N\] \[P=F\times v\] \[60\times 746=24000\times v\] \[\Rightarrow \text{ }v\text{ =}1.86\text{ }m/s\approx 1.9\text{ }m/s\]You need to login to perform this action.
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