A) +0.158 V
B) -0.158 V
C) -0.182 V
D) 0.182 V
Correct Answer: A
Solution :
[a] \[C{{u}^{2}}^{+}2{{e}^{-}}\to Cu,\Delta G_{1}^{{}^\circ }=-2F(0.34)...(i)\] \[C{{u}^{+}}+{{e}^{-}}\to Cu,\Delta G_{2}^{{}^\circ }=-F(0.522)...(ii)\] Subtract (ii) from (i) \[C{{u}^{2+}}+{{e}^{-}}\to C{{u}^{+}},\Delta G_{3}^{{}^\circ }=-F({{E}^{0}})\] \[\therefore \Delta G_{1}^{{}^\circ }-\Delta G_{2}^{{}^\circ }=\Delta G_{3}^{{}^\circ }\] \[\Rightarrow -FE{}^\circ =-2F(0.34)+F(0.522)\] \[\Rightarrow E{}^\circ =0.68-0.522=0.158\,\,V\]You need to login to perform this action.
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