(A) \[{{(C{{H}_{3}})}_{3}}CCH(OH)C{{H}_{3}}\xrightarrow{conc.{{H}_{2}}S{{O}_{4}}}\] |
(B) \[{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}\xrightarrow{alc.KOH}\] |
(C) \[{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}\xrightarrow{{{(C{{H}_{3}})}_{3}}{{O}^{\Theta }}{{K}^{\oplus }}}\] |
(D) \[{{(C{{H}_{3}})}_{2}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{2}}-CHO\xrightarrow{\Delta }\] |
A) (A), (C) and (D)
B) (C) only
C) (B) and (D)
D) (D) only
Correct Answer: B
Solution :
[b] Tertiary butoxide is a bulky base and it extracts the least hindered hydrogenYou need to login to perform this action.
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