JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Evening)

  • question_answer
    Consider the following plots of rate constant versus \[\frac{1}{T}\] for four different reactions. Which of the following orders is correct for the activation energies of these reactions?                        [JEE MAIN Held on 08-01-2020 Evening]

    A) \[{{E}_{b}}>{{E}_{a}}>{{E}_{d}}>{{E}_{c}}\]

    B) \[{{E}_{c}}>{{E}_{a}}>{{E}_{d}}>{{E}_{b}}\]

    C) \[{{E}_{a}}>{{E}_{c}}>{{E}_{d}}>{{E}_{b}}\]

    D) \[{{E}_{b}}>{{E}_{d}}>{{E}_{c}}>{{E}_{a}}\]

    Correct Answer: B

    Solution :

    \[logk=logA\frac{{{E}_{a}}}{2.303\,\,RT}\] \[Slope=\frac{{{E}_{a}}}{2.303\,\,R}\] So correct order of activation energies \[\Rightarrow \text{ }{{E}_{c}}>{{E}_{a}}>{{E}_{d}}>{{E}_{b}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner