A) Glucose reacts with hydroxylamine to form Oxime
B) The pentaacetate of glucose does not react With hydroxylamine to give oxime
C) Glucose exists in two crystalline forms \[\alpha \] and \[\beta \]
D) Glucose gives Schiff's test for aldehyde
Correct Answer: D
Solution :
[d] Glucose exists is two anomeric forms \[\alpha \] and\[\beta \]. It forms oxime with \[N{{H}_{2}}OH\]and its pentaacetate does not react with \[N{{H}_{2}}OH\] because its anomeric OH group is converted into acetate group. But glucose does not give Schiff test for aldehydeYou need to login to perform this action.
You will be redirected in
3 sec