JEE Main & Advanced
JEE Main Paper Phase-I (Held on 08-1-2020 Morning)
question_answer
A particle is moving along the x-axis with its coordinate with time 't' given by \[x\left( t \right)=10+8t3{{t}^{2}}.\] Another particle is moving along the y-axis with its coordinate as a function of time given by \[y\left( t \right)=58{{t}^{3}}.\] \[At\text{ }t=1\text{ }s,\] the speed of the second particle as measured in the frame of the first particle is given as \[\sqrt{v}\] . Then v (in m/s) is ________. [JEE MAIN Held On 08-01-2020 Morning]