A) \[\frac{945}{{{2}^{10}}}\]
B) \[\frac{965}{{{2}^{11}}}\]
C) \[\frac{965}{{{2}^{10}}}\]
D) \[\frac{945}{{{2}^{11}}}\]
Correct Answer: A
Solution :
Total ways of distribution \[={{4}^{10}}={{2}^{20}}\] Favourable ways Required probability \[=\frac{6\cdot 252\cdot \,10\,\cdot \,2\,\cdot \,{{2}^{5}}}{{{2}^{20}}}\] \[=\frac{3\times 63\times 5}{{{2}^{10}}}=\frac{945}{{{2}^{10}}}\]You need to login to perform this action.
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