A) \[ClCH=CHN{{O}_{2}}\]
B) \[ClCH=C{{H}_{2}}\]
C) \[ClCH=CHC{{H}_{3}}\]
D) \[ClCH=CHOC{{H}_{3}}\]
Correct Answer: A
Solution :
due to strong \[-R\] effect of \[-N{{O}_{2}}\] group, partial double bond character between C and \[Cl\]increases.
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