A) 1.83
B) 4.67
C) 2.3
D) 3.67
Correct Answer: A , B , C , D
Solution :
(1.09) Bonus \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] Mean free time, \[\tau =\frac{\lambda }{v}\] \[\tau \propto \frac{\sqrt{M}}{{{d}^{2}}}\] \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sqrt{{{M}_{1}}}}{{{d}_{1}}^{2}}\times \frac{{{d}_{2}}^{2}}{\sqrt{{{M}_{2}}}}\] \[=\sqrt{\frac{40}{140}}\times {{\left( \frac{0.1}{0.07} \right)}^{2}}=1.09\] None of the option matchesSolution :
(1.09) Bonus \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] Mean free time, \[\tau =\frac{\lambda }{v}\] \[\tau \propto \frac{\sqrt{M}}{{{d}^{2}}}\] \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sqrt{{{M}_{1}}}}{{{d}_{1}}^{2}}\times \frac{{{d}_{2}}^{2}}{\sqrt{{{M}_{2}}}}\] \[=\sqrt{\frac{40}{140}}\times {{\left( \frac{0.1}{0.07} \right)}^{2}}=1.09\] None of the option matchesSolution :
(1.09) Bonus \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] Mean free time, \[\tau =\frac{\lambda }{v}\] \[\tau \propto \frac{\sqrt{M}}{{{d}^{2}}}\] \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sqrt{{{M}_{1}}}}{{{d}_{1}}^{2}}\times \frac{{{d}_{2}}^{2}}{\sqrt{{{M}_{2}}}}\] \[=\sqrt{\frac{40}{140}}\times {{\left( \frac{0.1}{0.07} \right)}^{2}}=1.09\] None of the option matchesSolution :
(1.09) Bonus \[\lambda =\frac{1}{\sqrt{2}\pi {{d}^{2}}n}\] Mean free time, \[\tau =\frac{\lambda }{v}\] \[\tau \propto \frac{\sqrt{M}}{{{d}^{2}}}\] \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sqrt{{{M}_{1}}}}{{{d}_{1}}^{2}}\times \frac{{{d}_{2}}^{2}}{\sqrt{{{M}_{2}}}}\] \[=\sqrt{\frac{40}{140}}\times {{\left( \frac{0.1}{0.07} \right)}^{2}}=1.09\] None of the option matchesYou need to login to perform this action.
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