| B has a smaller first ionization enthalpy than Be. Consider the following statements. |
| (I) It is easier to remove 2p electron than 2s electron |
| (II) 2p electron of B is more shielded from the nucleus by the inner core of electrons than the 2s electrons of Be |
| (III) 2s electron has more penetration power than 2p electron |
| (IV) Atomic radius of B is more than Be (atomic number B = 5, Be = 4) |
| The correct statements are |
A) (I), (II) and (IV)
B) (I), (III) and (IV)
C) (I), (II) and (III)
D) (II), (III) and (IV)
Correct Answer: C
Solution :
[c] 1st I.E. of Be > B In case of Be, electron is removed from 2s orbital which has more penetration power, while in case of B electron is removed from 2p orbital which has less penetration power. 2p electron of B is more shielded from nucleus by the inner electrons than 2s electrons of Be \[\therefore \] It is easier to remove 2p electron than 2s electron.
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