A) 14
B) 15
C) 17
D) 16
Correct Answer: D
Solution :
[d] \[\because \,\,\,\,\,\,\,\,\,\,\,\,e_{1}^{2}=1-\frac{{{b}^{2}}}{{{a}^{2}}}=1-\frac{4}{18}=\frac{7}{9}\] and \[e_{2}^{2}=1+\frac{{{b}^{2}}}{{{a}^{2}}}=1+\frac{4}{9}=\frac{13}{9}\] \[\because \]\[({{e}_{1}},{{e}_{2}})\] lies on \[15{{x}^{2}}+3{{y}^{2}}=k\] So \[k=15e_{1}^{2}+3e_{2}^{2}=\frac{35}{3}+\frac{13}{3}=16\]You need to login to perform this action.
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