A) \[\frac{1}{36\pi }\]
B) \[\frac{1}{18\pi }\]
C) \[\frac{1}{54\pi }\]
D) \[\frac{5}{6\pi }\]
Correct Answer: B
Solution :
[b] \[V=\frac{4}{3}\pi \left[ {{\left( 10+\omega \right)}^{3}}-{{10}^{3}} \right]\] \[\frac{dv}{dt}=\frac{4}{3}\pi \left[ 3{{\left( 10+\omega \right)}^{2}}\frac{d\omega }{dt} \right]=50\] when \[\omega =5\] \[\Rightarrow \,\,\,\,\,\,\,\frac{d\omega }{dt}=\frac{3\times 50}{4\pi {{.3.15}^{2}}}\] \[=\frac{1}{18\pi }\]You need to login to perform this action.
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