A) \[(6,\,3)\]
B) \[(3,\,6)\]
C) \[(3,\,3)\]
D) \[(6,\,6)\]
Correct Answer: C
Solution :
[c] Let \[({{x}_{i}}-5)={{y}_{i}}\] So \[\overline{y}=\frac{\sum{{{y}_{i}}}}{10}=\frac{10}{10}=1\] and \[Var\,\,(y)=\frac{\sum{y_{i}^{2}}}{10}-{{(\bar{y})}^{2}}=3\] Now mean of \[({{x}_{i}}-3)=({{y}_{i}}+2)\]is \[\bar{y}+2,\] which is 3. And variance remains same.You need to login to perform this action.
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