JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    If z is a complex number such that\[|z|\ge 2,\]then the minimum value of \[\left| z+\frac{1}{2} \right|:\]   JEE Main  Solved  Paper-2014

    A) is equal to \[\frac{5}{2}\]

    B) lies in the interval (1, 2)

    C) is strictly greater than \[\frac{5}{2}\]

    D) is strictly greater than \[\frac{3}{2}\]but less than \[\frac{5}{2}\]

    Correct Answer: B

    Solution :

    \[\left| z+\frac{1}{2} \right|=\left| z-\left( -\frac{1}{2} \right) \right|\]The minimum value of\[\left| z+\frac{1}{2} \right|\]is\[\frac{3}{2}\]

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