A) equivalent to \[p\leftrightarrow q\]
B) equivalent to \[\tilde{\ }p\leftrightarrow q\]
C) a tautology
D) a fallacy
Correct Answer: A
Solution :
Truth table for \[\tilde{\ }(p\leftrightarrow \tilde{\ }q)\]is(1) | (2) | (3) | ||||
\[p\] | \[q\] | \[\tilde{\ }q\] | \[p\to \tilde{\ }q\] | \[\tilde{\ }q\to p\] | \[(1)\wedge (2)\] | \[\tilde{\ }(3)\] |
\[T\] | \[T\] | \[F\] | \[F\] | \[T\] | \[F\] | \[T\] |
\[T\] | \[F\] | \[T\] | \[T\] | \[T\] | \[T\] | \[F\] |
\[F\] | \[F\] | \[T\] | \[T\] | \[F\] | \[F\] | \[T\] |
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