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JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    In the reaction, \[C{{H}_{3}}COOH\xrightarrow[{}]{LiAl{{H}_{4}}}A\xrightarrow[{}]{PC{{l}_{5}}}B\xrightarrow[{}]{Alc.KOH}C,\]the product C is :   JEE Main  Solved  Paper-2014

    A) Ethylene             

    B)  Acetyl chloride

    C) Acetaldehyde   

    D) Acetylene

    Correct Answer: A

    Solution :

    \[C{{H}_{3}}-\overset{\begin{smallmatrix}  O \\  || \end{smallmatrix}}{\mathop{C}}\,-OH\xrightarrow[{}]{LiA\ell {{H}_{4}}}C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[{}]{{{P}_{C}}{{l}_{5}}}\] \[{{C}_{2}}{{H}_{5}}C\ell \xrightarrow[{}]{Alc.KOH}C{{H}_{2}}=C{{H}_{2}}\]                


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