JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    If \[X=\{{{4}^{n}}-1:n\varepsilon N\}\] and\[Y=\{9(n-1):n\varepsilon N\},\] where N is the set of natural numbers, then \[X\cup Y\] is equal to :   JEE Main  Solved  Paper-2014

    A) N                                            

    B) Y − X

    C) X                                            

    D) Y

    Correct Answer: D

    Solution :

    \[x={{4}^{n}}-3n-1,n\in N\] \[x={{(1+3)}^{n}}-3n-1,n\in N\] \[\Rightarrow \]\[X=0,9,54,.....\] \[y=9(n-1),n\in N\] \[\Rightarrow \]\[y=0,9,18,....\] \[\Rightarrow \]\[x\cup y=y.\]

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