JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    When a rubber-band is stretched by a distance x, it exerts a restoring force of magnitude\[F=ax+b{{x}^{2}}\]where a and b are constants. The work done in stretching the unstretched rubber-band by Lis :   JEE Main  Solved  Paper-2014

    A) \[\frac{a{{L}^{2}}}{2}+\frac{b{{L}^{3}}}{3}\]         

    B) \[\frac{1}{2}\left[ \frac{a{{L}^{2}}}{2}+\frac{b{{L}^{3}}}{3} \right]\]

    C)  \[a{{L}^{2}}+b{{L}^{3}}\]                             

    D)  \[\frac{1}{2}(a{{L}^{2}}+b{{L}^{3}})\]

    Correct Answer: A

    Solution :

    \[w=\int\limits_{0}^{L}{F.}dx\Rightarrow \omega =\frac{a{{L}^{2}}}{2}+\frac{b{{L}^{3}}}{3}\]


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