A) Ethylene
B) Acetyl chloride
C) Acetaldehyde
D) Acetylene
Correct Answer: A
Solution :
\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH\xrightarrow[{}]{LiA\ell {{H}_{4}}}C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[{}]{{{P}_{C}}{{l}_{5}}}\] \[{{C}_{2}}{{H}_{5}}C\ell \xrightarrow[{}]{Alc.KOH}C{{H}_{2}}=C{{H}_{2}}\]You need to login to perform this action.
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