A) is equal to \[\frac{5}{2}\]
B) lies in the interval (1, 2)
C) is strictly greater than \[\frac{5}{2}\]
D) is strictly greater than \[\frac{3}{2}\]but less than \[\frac{5}{2}\]
Correct Answer: B
Solution :
\[\left| z+\frac{1}{2} \right|=\left| z-\left( -\frac{1}{2} \right) \right|\]The minimum value of\[\left| z+\frac{1}{2} \right|\]is\[\frac{3}{2}\]You need to login to perform this action.
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