JEE Main & Advanced JEE Main Solved Paper-2014

  • question_answer
    The equation which is balanced and represents the correct product(s) is :   JEE Main  Solved  Paper-2014

    A) \[{{[Mg{{({{H}_{2}}O)}_{6}}]}^{2+}}+{{(EDTA)}^{4-}}\xrightarrow[{}]{excessNaOH}{{[Mg(EDTA)]}^{2}}+6{{H}_{2}}O\]

    B) \[CuS{{O}_{4}}+4KCN\to {{K}_{2}}[Cu{{(CN)}_{4}}]+{{K}_{2}}S{{O}_{4}}\]

    C) \[L{{i}_{2}}+2KCl\to 2LiCl+{{K}_{2}}O\]

    D) \[[CoCl{{(N{{H}_{3}})}_{5}}]++5{{H}^{+}}\to C{{o}^{2+}}+5NH_{4}^{+}+C{{l}^{-}}\]

    Correct Answer: C

    Solution :

    Factual


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