A) \[2.2\times {{10}^{7}}Pa\]
B) \[2.2\times {{10}^{6}}Pa\]
C) \[2.2\times {{10}^{8}}Pa\]
D) \[2.2\times {{10}^{9}}Pa\]
Correct Answer: C
Solution :
\[\frac{F}{A}=Y\frac{\Delta \ell }{\ell }\] \[\frac{\Delta \ell }{\ell }=\alpha \Delta T\] \[P=\frac{F}{A}=Y\alpha \Delta T\] \[=2\times {{10}^{11}}\times 1.1\times {{10}^{-5}}\times 100=2.2\times {{10}^{8}}N/{{m}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec