A) 38 cm
B) 6 cm
C) 16 cm
D) 22 cm
Correct Answer: A
Solution :
\[P'(54-h)={{P}_{0}}8\] (Boyel?s law) \[P'=\frac{{{P}_{0}}8}{(54-h)}\] \[P'+\rho gh={{P}_{0}}\] \[\frac{8{{P}_{0}}}{54-h}+\rho gh={{P}_{0}}\] \[\rho gh=\left( \frac{46-h}{54-h} \right){{P}_{0}}\] \[({{P}_{0}}=\rho g(76))\] \[h=\left( \frac{46-h}{54-h} \right)(76)\] \[\Rightarrow \]\[54h-{{h}^{2}}=76\times 46-76h\] \[{{h}^{2}}-130h+76\times 46=0\] \[(h-38)(h-92)=0\] \[h=38,\underset{\text{Not}\,\text{possible}}{\mathop{\underset{\downarrow }{\mathop{92}}\,}}\,\]\[\Rightarrow \]\[h=38cm\]You need to login to perform this action.
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