A) \[\frac{1}{3}m\]
B) \[\frac{1}{2}m\]
C) \[\frac{1}{6}m\]
D) \[\frac{2}{3}m\]
Correct Answer: C
Solution :
\[mg\sin \theta ={{\mu }_{s}}mg\cos \theta \] [when partied is just balanced] \[\Rightarrow \]\[\tan \theta ={{\mu }_{s}}\] \[\tan \theta =\frac{dy}{dx}=\left( \frac{{{x}^{2}}}{2} \right)\] \[\therefore \]\[\frac{{{x}^{2}}}{2}=0.5\Rightarrow x=1\]\[\Rightarrow \]\[y=\frac{1}{6}\]You need to login to perform this action.
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