A) 0.5 mA
B) 0.05 mA
C) 0.2 mA
D) 0.02 mA
Correct Answer: C
Solution :
\[I=\left( {{e}^{\frac{^{1000V}}{T}}}-1 \right)\] \[\frac{dl}{dV}=\frac{1000}{T}{{e}^{\frac{1000V}{T}}}\] \[dI=\left( \frac{1000}{T}{{e}^{\frac{1000V}{T}}} \right)dV\] \[I=5MA\] \[\Rightarrow \]\[e\frac{1000V}{T}=6MA\] \[dI=\left( \frac{1000}{300} \right)(0.01)(6)=\frac{10}{50}=\frac{1}{5}\] \[dI=0.2mA\]You need to login to perform this action.
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