A) 6
B) 4
C) 12
D) 8
Correct Answer: A
Solution :
\[L=n\frac{\lambda }{2}+\frac{\lambda }{4}=(2n+1)\frac{\lambda }{4}=\frac{(2n+1)v}{4f}\] \[\Rightarrow \]\[0.85=\frac{{{(2n+1)}^{v}}}{4f}\]\[\Rightarrow \]\[f=\frac{(2n+1)\times 85}{0.85\times 4}\] \[\Rightarrow \]\[f=(2n+1)100{{H}_{2}}\]\[\Rightarrow \]\[\Rightarrow \] The possible frequencies are: \[100Hz,300Hz,...1100Hz.\]You need to login to perform this action.
You will be redirected in
3 sec