A) \[{{r}_{Cs}}+{{r}_{Cl-}}=\frac{\sqrt{3}}{2}a\]
B) \[{{r}_{Cs}}{{+}_{C{{l}^{-}}}}=\sqrt{3}a\]
C) \[{{r}_{Cs}}_{+}{{+}_{C{{l}^{-}}}}=3a\]
D) \[{{r}_{Cs}}_{+}+{{r}_{C{{l}^{-}}}}=\frac{3a}{2}\]
Correct Answer: A
Solution :
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