A) \[{{\lambda }_{C}}={{\lambda }_{\infty }}-(B)\sqrt{C}\]
B) \[{{\lambda }_{C}}={{\lambda }_{\infty }}+(B)\sqrt{C}\]
C) \[{{\lambda }_{C}}={{\lambda }_{\infty }}+(B)C\]
D) \[{{\lambda }_{C}}={{\lambda }_{\infty }}-(B)C\]
Correct Answer: A
Solution :
Variation of \[{{\lambda }_{c}}\] for strong electrotype is given by \[{{\lambda }_{c}}={{\lambda }_{\infty }}-B\sqrt{C}\]You need to login to perform this action.
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