A) \[\sqrt{2}+\sqrt{3}\]
B) \[3+\sqrt{2}\]
C) \[2-\sqrt{3}\]
D) \[2+\sqrt{3}\]
Correct Answer: D
Solution :
Let the numbers be \[\text{a,ar,a}{{\text{r}}^{\text{2}}}\] is G.P. Given a, 2ar, ar2 are in A.P. the\[2ar=\frac{a+a{{r}^{2}}}{2}(a\ne 0)\]which gives \[r+2+\sqrt{3},\]r = 2 + 3 , as the G.P. is an increasing G.P.
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