JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    A signal of 5 kHz frequency is amplitude modulated on a carrier wave of frequency 2 MHz. The frequencies of the resultant signal is / are : [JEE Main Solved Paper-2015 ]

    A)  2005 kHz, 2000 kHz and 1995 kHz

    B) 2000 kHz and 1995 kHz

    C) 2 MHz only

    D) 2005 kHz, and 1995 kHz

    Correct Answer: A

    Solution :

                   
    \[{{A}_{M}}-{{A}_{C}}\] \[{{A}_{M}}\] \[{{A}_{M}}+{{A}_{C}}\]
    \[1995\,KHz\] \[2000\] \[2005\]


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