A) \[\left[ 1-{{\left( \frac{{{T}_{M}}}{T} \right)}^{2}} \right]\frac{A}{Mg}\]
B) \[\left[ 1-{{\left( \frac{T}{{{T}_{M}}} \right)}^{2}} \right]\frac{A}{Mg}\]
C) \[\left[ {{\left( \frac{{{T}_{M}}}{T} \right)}^{2}}-1 \right]\frac{A}{Mg}\]
D) \[\left[ {{\left( \frac{{{T}_{M}}}{T} \right)}^{2}}-1 \right]\frac{Mg}{A}\]
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{\ell }{g}}\] \[{{T}_{M}}=2\pi \sqrt{\frac{\ell }{g}}\] \[{{T}_{M}}=2\pi \sqrt{\frac{\frac{{{\ell }_{0}}\left( 1+\frac{F}{AY} \right)}{g}}{{}}}\] \[{{T}_{M}}={{T}_{0}}\sqrt{\left( 1+\frac{F}{AY} \right)}\] \[{{\left( \frac{{{T}_{M}}}{{{T}_{0}}} \right)}^{2}}=1+\frac{F}{AY}\] \[\frac{F}{AY}={{\left( \frac{{{T}_{M}}}{{{T}_{0}}} \right)}^{2}}-1\] \[\frac{1}{Y}=\frac{A}{F}{{\left( 1-\frac{{{T}_{M}}}{{{T}_{0}}} \right)}^{2}}\] \[\frac{1}{Y}=\frac{A}{mg}\left( {{\left( \frac{{{T}_{M}}}{{{T}_{0}}} \right)}^{2}}-1 \right)\]You need to login to perform this action.
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