2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    Two Faraday of electricity is passed through a solution of \[CuS{{O}_{4}}.\] The mass of copper deposited at the cathode is : (at. mass of Cu = 63.5 amu)                 [JEE Main Solved Paper-2015 ]

    A) 2 g                                         

    B) 127 g

    C) 0 g                                         

    D) 63.5 g

    Correct Answer: D

    Solution :

    \[1F\xrightarrow[{}]{{}}1eq.wt.\] \[C{{u}^{2+}}+2_{2F}^{{{e}^{-}}}\xrightarrow[{}]{{}}\underset{1mol}{\mathop{Cu}}\,\] 2 Faraday’s electricity deposit\[\to \] 63.5 g of Cu.


You need to login to perform this action.
You will be redirected in 3 sec spinner