JEE Main & Advanced JEE Main Solved Paper-2015

  • question_answer
    Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set \[A\times B,\] each having at least three elements is : [JEE Main Solved Paper-2015 ]

    A)

    B) 275                                        

    C) 510

    D) 219                                        

    E) 256

    Correct Answer: D

    Solution :

    \[n\left( A \right)=4\]and\[n\left( B \right)=2\] \[\Rightarrow \]\[\eta (A\times B)=8\] Hence number of subsets of \[(A\times B)\]each having at least three elements is equal to \[^{8}{{C}_{3}}{{+}^{8}}{{C}_{4}}{{+}^{8}}{{C}_{5}}+.....{{+}^{8}}{{C}_{8}}\] \[={{2}^{8}}{{-}^{8}}{{C}_{0}}{{+}^{8}}{{C}_{1}}{{-}^{8}}{{C}_{2}}\] \[=256-1-8-28=219\]


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