athematics The area (in sq. units ) of the region described by
[JEE Main Solved Paper-2015 ]
A)\[\frac{15}{64}\]
B)\[\frac{9}{32}\]
C)\[\frac{7}{32}\]
D)\[\frac{5}{64}\]
Correct Answer:
B
Solution :
The required region is shown shaded. The points of intersections are\[\left( \frac{1}{8},-\frac{1}{2} \right)\And \left( \frac{1}{2},1 \right)\] \[\Rightarrow \]Required area\[=\int\limits_{-\frac{1}{2}}^{1}{\left( \frac{y+4}{4}-\frac{{{y}^{2}}}{2} \right)dy=\frac{9}{32}}\]