A) \[{{y}^{2}}=2x\]
B) \[{{x}^{2}}=2y\]
C) \[{{x}^{2}}=y\]
D) \[{{y}^{2}}=x\]
Correct Answer: B
Solution :
Any point on the curve \[{{x}^{2}}=8y\]is \[(4t,2{{t}^{2}})\] Point P(h,x) divides the line segment joining OQ in ratio 1 : 3 \[\Rightarrow \]\[h=\frac{4t}{4}=t\And k=\frac{2{{t}^{2}}}{4}=\frac{{{t}^{2}}}{2}\] Hence locus of point P is \[{{x}^{2}}=2y\]You need to login to perform this action.
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