A) 0.29 and 6.5 m
B) 0.2 and 6.5 m
C) 0.2 and 3.5 m
D) 0.29 and 3.5 m
Correct Answer: D
Solution :
Energy lost over path PQ is \[=\mu mg\cos \theta \times 4\] Energy lost over path QR is \[=\mu mgx\] \[=\mu mgx=\mu mg\cos \theta \times 4\] \[x=\cos \theta \times 4\] \[\] From Q to R energy loss is half of the total energy loss. \[\mu mgx=\frac{1}{2}\times mgh\Rightarrow \mu =0.29\]You need to login to perform this action.
You will be redirected in
3 sec