2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Solved Paper-2016

  • question_answer
    A satellite is reolving in a circular orbit at a height 'h' from the earth's surface (radius of earth R ; h << R). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth's gravitational field, is close to : (Neglect the effect of atmosphere). [JEE Main Solved Paper-2016 ]

    A) \[\sqrt{gR}\left( \sqrt{2}-1 \right)\]        

    B) \[\sqrt{2gR}\]

    C) \[\sqrt{gR}\]                     

    D) \[\sqrt{gR/2}\]

    Correct Answer: A

    Solution :

                    \[{{V}_{0}}=\sqrt{\frac{GM}{R}}\]or\[\sqrt{gR}\] \[{{V}_{e}}\sqrt{\frac{2GM}{R}}\]or\[\sqrt{2gR}\] \[\therefore \]Increase in velocity \[=\sqrt{gR}\left[ \sqrt{2}-1 \right]\]


You need to login to perform this action.
You will be redirected in 3 sec spinner