A) 2
B) 26
C) 18
D) 5
Correct Answer: A
Solution :
Given line\[\frac{x-3}{2}=\frac{y+2}{-1}=\frac{z+4}{3}\]and Given plane is \[\ell x+my-z=9\] Now, it is given that line lies on plane \[\therefore \]\[2\ell -m-3=0\Rightarrow 2\ell -m=3\] ...(1) Also, (3, ?2, ?4) lies on plane\[3\ell -2m=5\]...(2) Solving (1) and (2), we get \[\ell =1,m=-1\]\[\therefore \]\[{{\ell }^{2}}+{{m}^{2}}=2\]You need to login to perform this action.
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