A) \[\left( -\frac{10}{3},\frac{7}{3} \right)\]
B) \[(-3,-9)\]
C) \[(-3,-8)\]
D) \[\left( \frac{1}{3},\frac{8}{3} \right)\]
Correct Answer: D
Solution :
Equation of angle bisector of the lines \[\text{x}\text{y}+\text{1}=0\]and \[\text{7x}\text{y}\text{5}=0\] is given by \[\frac{x-y+1}{\sqrt{2}}=\pm \frac{7x-y-5}{5\sqrt{2}}\] \[\Rightarrow \]\[5(x-y+1)=7x-y-5\] \[\therefore \]\[2x+4y-10=0\Rightarrow x+2y-5=0\]and Now equation of diagonals are \[(x+1)+2y(y+2)=0\Rightarrow x+2y+5=0\] ..(1) and\[2(x+1)-(y+2)=0\Rightarrow 2x-y=0\] ...(2) Clearly\[\left( \frac{1}{3},\frac{8}{3} \right)\]lies on (1)You need to login to perform this action.
You will be redirected in
3 sec