A) 480 N/C
B) 240 N/C
C) 360 N/C
D) 420 N/C
Correct Answer: D
Solution :
\[\text{Q}=\text{24}+\text{18}=\text{42}\mu \text{c}\] \[E=\frac{KQ}{{{r}^{2}}}\] \[\Rightarrow \]\[E=\frac{9\times {{10}^{9}}\times 42\times {{10}^{-6}}}{{{(30)}^{2}}}=420N/C\]You need to login to perform this action.
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