A) \[\frac{\pi }{2}=\frac{2\sqrt{2}}{3}\]
B) \[\pi -\frac{4}{3}\]
C) \[\pi -\frac{4}{3}\]
D) \[\pi -\frac{4\sqrt{2}}{3}\]
Correct Answer: C
Solution :
\[=\pi \frac{\pi {{(2)}^{2}}}{4}-\sqrt{2}\int\limits_{0}^{2}{\sqrt{x}}dx\] \[=\pi -\sqrt{2}.\frac{2}{3}2\sqrt{2}\] \[=\pi -8/3\]You need to login to perform this action.
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