A) \[\sqrt{2meV}\]
B) 2meV
C) 2meV
D) \[\sqrt{meV}\]
Correct Answer: A
Solution :
As electron of charge 'e' is passed through 'V' volt, kinetic energy of electron becomes = 'eV' As wavelength of \[{{e}^{-}}\] wave \[(\lambda )=\frac{h}{\sqrt{2mK.E.}}\] \[\lambda =\frac{h}{\sqrt{2meV}}\] \[\therefore \]\[\frac{h}{\lambda }=\sqrt{2meV}\]You need to login to perform this action.
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