A) 9 J
B) 18 J
C) 4.5 J
D) 22 J
Correct Answer: C
Solution :
\[F=6t=ma\] \[\Rightarrow \] \[a=6t\] \[\Rightarrow \] \[\frac{dv}{dt}=6t\] \[\int_{0}^{v}{dv}=\int_{0}^{1}{6t}\,dt\] \[v=(3{{t}^{2}})_{0}^{1}=3\,m/s\] From work energy theorem \[{{W}_{F}}=\Delta K.E=\frac{1}{2}m\left( {{v}^{2}}-{{u}^{2}} \right)\] \[=\frac{1}{2}(1)(9-0)=4.5\,J\]
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