A) 250 Wb
B) 275 Wb
C) 200 Wb
D) 225 Wb
Correct Answer: A
Solution :
\[q=\frac{\Delta \text{o}|}{R}\] \[\Delta \text{o }\!\!|\!\!\text{ }=\]change in flux \[q=\int_{{}}^{{}}{I\,dt}\] = Area of current-time graph \[=\frac{1}{2}\times 10\times 0.5=2.5\]coloumb \[q=\frac{\Delta \text{o}|}{R}\] \[\Delta \text{o }\!\!|\!\!\text{ =2}\text{.5}\times 100=250\,Wb\]You need to login to perform this action.
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