A) \[{{C}_{6}}{{H}_{5}}COONa\]
B) \[HCOONa\]
C) \[CH3COONa\]
D) \[N{{a}_{2}}{{C}_{2}}{{O}_{4}}\]
Correct Answer: D
Solution :
\[N{{a}_{2}}{{C}_{2}}{{O}_{4}}+\underset{\text{conc}\text{.}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+CO\uparrow \] \[+C{{O}_{2}}\infty \uparrow +{{H}_{2}}O\]\[N{{a}_{2}}{{C}_{2}}{{O}_{4}}+CaC{{l}_{2}}\xrightarrow{{}}\underset{(white\,ppt.)}{\mathop{Ca{{C}_{2}}{{O}_{4}}}}\,\downarrow 2NaCl\]You need to login to perform this action.
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