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JEE Main & Advanced JEE Main Solved Paper-2017

  • question_answer
    A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is 'a', the closest approach between two atoms in metallic crystal will be :-     JEE Main Solved Paper-2017

    A)  2a                                         

    B)  \[2\sqrt{2}a\]

    C)  \[\sqrt{2}a\]                     

    D)  \[\frac{a}{\sqrt{2}}\]

    Correct Answer: D

    Solution :

     In FCC unit cell atoms are in contant along face diagonal So, \[\sqrt{2}a=4R\] \[\therefore \] closest distance \[(2R)=\frac{\sqrt{2}a}{2}=\frac{a}{\sqrt{2}}\]


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